A point on the line `(x-1)/1=(y-2)/2=(z+1)/3` at a distance `sqrt(6)` from the origin is (A) `((-5)/7, (-10)/7,13/7)` (B) `(5/7,10/7,(-13)/7)` (C) `(1,2,-1)` (D) `(-1,-2,1)`

The reflection of the point (2,-1,3) in the plane 3x-2y-z=9 is (A) (28/7,15/7,17/7) (B) (26/7,-15/7,17/7) (C) (15/7,26/,-17/7) (D) (26/7,17/7,-15/70)

The point of intersection of the lines (x-5)/3=(y-7)/(-1)=(z+2)/1 and (x+3)/(-36)=(y-3)/2=(z-6)/4 is (A) (21, 5/3, 10/3) (B) (2,10,4) (C) (-3,3,6) (D) (5,7,-2)

Statement 1: A point on the line (x+2)/3=(y+1)/2=(z-3)/2 at a distance 3sqrt(2) from the point (1,2,3) lies on the lne (x+7)/5=(y+t)/4=(z-2)/1 Statement 2: If d is the distance between the point (-1,-5,-10) and the point of intersectionof the line (x-2)/3=(y+1)/4=(z-2)/12 with the plane x-y+z=5 then d=13

Perpendiculars are drawn from points on the line (x+2)/(2)=(y+1)/(-1)=(z)/(3) to the plane x+y+z=3 The feet of perpendiculars lie on the line (a) (x)/(5)=(y-1)/(8)=(z-2)/(-13) (b) (x)/(2)=(y-1)/(3)=(z-2)/(-5)(d)(x)/(4)=(y-1)/(-7)=(z-2)/(5)(d)(x)/(2)=(y-1)/(-7)=(z-2)/(5)

The perpendicular distance from (1,2) to the straight line 12x+5y=7 is (i)(15)/(13) (ii) (12)/(13) (iii) (5)/(13) (iv) (7)/(13)

The point of intersection of the lines (x-5)/(3)=(y-7)/(-1)=(z+2)/(1) and (x+3)/(-36)=(y-3)/(2)=(z-6)/(4) is (A) (21,(5)/(3),(10)/(3))(B)(2,10,4)(C)(-3,3,6)(D)(5,7,-2)

The distance of the plane vecr.(2/7hati+3/7hatj-6/7hatk)=1 from the origin is (A) 1 (B) 7 (C) 1/7 (D) none of these

The sum of the infinite series is (1)/(1.3)+(1)/(3.5)+(1)/(5.7)+...oo(A)(1)/(7)(B)(1)/(3)(C)(1)/(5) (D) (1)/(2)

If projections of as line on x,y and z axes are 6,2 and 3 respectively, then directions cosines of the lines are (A) (6/2,2/7,3/7) (B) (3/5,5/7,6/7) (C) (1/7,2/7,3/7) (D) none of these

The position vector of the point, which divides the line segment joining the points (1,3,-9) and (6,-2,-4) in the ratio 2:3 is A) (3,-1,-7) B) (-3, 1, -7) C) (3, 1, -7) D) (-3,-1,7)