If `veca,vecb,vecc` are unit vectors such that `veca+vecb+vecc=0 then veca.vecb+vecb.vecc+vecc.veca=` (A) `3/2` (B) `-3/2` (C) `2/3` (D) `1/2`

If veca,vecb,vecc are three unit vectors such that veca+vecb+vecc=0, then veca.vecb+vecb.vecc+vecc.veca is equal to (A) -1 (B) 3 (C) 0 (D) -3/2

If veca,vecbandvecc are unit vectors such that veca+vecb+vecc=0 , then the value of veca.vecb+vecb.vecc+vecc.veca is

If veca, vecb, vecc are vectors such that veca.vecb=0 and veca + vecb = vecc then:

If veca, vecb are the unit vectors such that veca + 2vecb + 2vecc=0 , then |veca xx vecc| is equal to:

If veca, vecb, vecc are three non-zero vectors such that veca + vecb + vecc=0 and m = veca.vecb + vecb.vecc + vecc.veca , then:

If two out to the three vectors , veca, vecb , vecc are unit vectors such that veca + vecb + vecc =0 and 2(veca.vecb + vecb .vecc + vecc.veca) +3=0 then the length of the third vector is

If veca, vecb, vecc are vectors such that |vecb|=|vecc| then {(veca+vecb)xx(veca+vecc)}xx(vecbxxvecc).(vecb+vecc)=

If |veca|=1,|vecb|=2,|vecc|=3and veca+vecb+vecc=0 the show that veca.vecb+vecb.vecc+vecc.veca=- 7

veca,vecb,vecc are 3 vectors, such that veca+vecb+vecc=0, |veca|=1,|vecb|=2,|vecc|=3, then veca.vecb+vecb.vecc+veca.veca is equal to (A) 0 (B) -7 (C) 7 (D) 1