Given two vectors are `hati-hatj and hati+2hatj`. The unit vector coplanar with the two vectors nad perpendicular to first is (A) `1/sqrt(2)(hati+hatj)` (B) `1/sqrt(5)(2hati+hatj)` (C) `+-1/sqrt(2)(hati+hatj)` (D) none of these

Given, two vectors are hati - hatj and hati + 2hatj , the unit vector coplanar with the two vectors and perpendicular to first is:

The sides of a parallelogram are 2hati+4hat-5hatk and hati+2hatj+3hatk . The unit vector parallel to one of the diagonal is (A) 1/sqrt(69)(hati+2hatj-8hatk) (B) 1/sqrt(69)(-hati+2hatj+8hatk) (C) 1/sqrt(69)(-hati-2hatj-8hatk) (D) 1/sqrt(69)(hati+2hatj+8hatk)

If a=2hati+5hatj and b=2hati-hatj , then the unit vector along a+b will be

Let a=2hati+hatj+hatk,b=hati+2hatj-hatk and c is a unit vector coplanar to them. If c is perpendicular to a, then c is equal to

Show that (hati-hatj)/sqrt2 is a unit vector.

Three vectors a=hati+hatj-hatk, b=-hati+2hatj+hatk and c=-hati+2hatj-hatk , then the unit vector perpendicular to both a+b and b+c is