Let the line `(x-2)/3=(y-1)/-5=(z+2)/2` lie in the plane `x+3y-alpha z+beta=0` then `(alpha, beta)` equals (A) (6,-17) (B) (-6,7) (C) (5,-15) (D) (-5,15)

Let the line (x-2)/3=(y-1)/(-5)=(z+2)/2 lie in the plane x+3y-alphaz+beta=0. Then (alpha,beta) equals (A) (6,-17) (B) (-6,7) (C) (5,15) (D) (-5,5)

Let the line (x-2)/3 = (y-1)/-5 =(z+2)/2 lie in the plane x+3y - alphaz + beta=0 . Then, (alpha,beta) equals

Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) lies in the plane x+3y-alpha z +beta=0 . Then, (alpha,beta) equals

Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) lies in the plane x+3y-alphaz+beta=0 . Then, (alpha, beta) equals

If the line (x-2)/3 =(y-1)/-5 =(z+2)/2 lies in the plane x+3y - alphaz + beta=0 , then: (alpha, beta)-=

If the line (x-2)/(3)=(y+1)/(5)=(z-2)/(2) lies in the plane alpha x+2y+z-beta=0 then (alpha, beta) equals

Let the line (x-2)/3=(y-1)/(-5)=(z+2)/2 lie in the plane x""+""3y""alphaz""+beta=""0 . Then (alpha,beta) equals (1) (6,""""-17) (2) (-6,""7) (3) (5,"" -15) (4) (-5,""5)

Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) lie in the plane x+3y-alpha z+ beta=0 then the value of alpha+beta=