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cos20^(@)*cos40^(@)*cos80^(@)=?...

cos20^(@)*cos40^(@)*cos80^(@)=?

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cos20^(@)cos40^(@)cos60^(@)cos80^(@)=

cos 20^(@) cos 40^(@) cos 80^(@)=

Prove that cos 20^(@) cos 40^(@) cos 80^(@) = (1)/(8).

Prove that cos 20^(@) cos 40^(@) cos 80^(@)=1/8

Prove that cos 20^(@) cos 40^(@) cos 80^(@)=1/8

cos20^(@).cos40^(@).cos60^(@).cos80^(@) is :

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

The value of cos 20^(@) cos 40^(@)cos 60^(@) cos 80^(@) is equal to

cos 20^(@) cos 40^(@) cos 80^(@)= ............ A) 1/2 B) 1/4 C) 1/6 D) 1/8