3, A function f: R. ? R, defined as Then `{f(xy)}^2=x*(f(y))^2 , f(2)=6` then `f(100)`

A function R^(+)rarr R^(+) defined as Then (f(xy))^(2)=x(f(y))^(2) and f(2)=6 then f(100) is (A)300(B)30sqrt(2)(C)50sqrt(2)(D)100

The function f:R to R defined as f(x)=x^(2) . The function f is

A function f : R -> R^+ satisfies f(x+y)= f(x) f(y) AA x in R If f'(0)=2 then f'(x)=

(f(x y))^2=x(f(y))^2:f(2)=6 A function f: R+ ? R+ defined as Then f(100) =?

(f(x y))^2=x(f(y))^2:f(2)=6 A function f: R+ ? R+ defined as Then f(100) =?

(f(x y))^2=x(f(y))^2:f(2)=6 A function f: R+ ? R+ defined as Then f(100) =?

If the function f: R to R is defined by f(x)=x^(2)-6x-14 , then f^(-1)(2) is equal to -

If the function f: R to R defined by f(x)=(3^(x)+3^(-x))/(2) , then S.T f(x+y)+f(x-y)=2f(x)f(y) .

Consider the function f:R rarr R defined by f(x)=|x-1| . Is f(2)=f(0) ,why?