pH of when 50mL of 0.10 M ammonia solution is treated with 50 mL of 0.05 M HCI solution :-
`(pK_(b) "of ammonia"=4.74)`

Calculate the pH after 50.0 mL of 0.1 M ammonia solution is treated with 25.0 mL of 0.10 M HCl. The dissociation constant of ammonia , K_b=1.77xx10^(-5)

50 mL of 0.2 M ammonia solution is treated with 25mL of 0.2 M HCl . If pK_(b) of ammonia solution is 4.75 , the pH of the mixture will be

50 mL of 0.2M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_(b) of ammonia solution is 4.75 the pH of the mixture will be :

50.0 mL of 0.10 M ammonia solution is treated with 25.0 mL of 0.10M HCI . If K_(b)(NH_(3))=1.77xx10^(-5) , the pH of the resulting solution will be

50.0 mL of 0.10 M ammonia solution is treated with 25.0 mL of 0.10M HCI . If K_(b)(NH_(3))=1.77xx10^(-5) , the pH of the resulting solution will be

Calculate the pH of 0.10M ammonia solution. Calcualte the pH after 50.0mL of this solution is treated with 25.0mL of 0.10M HCl . The dissociation constant of ammonia, K_(b)=1.77xx10^(-5) .