A `DeltaABC` is formed by the lines `2x-3y-6 = 0,3x-y+3=0 and 3x-4y-12 = 0` . lf the points `P(alpha,0) and Q(0,beta)` always lie on or inside the `DeltaABC`, then:

DeltaABC is formed by the lines 2x-3y-6=0, 3x-y+3=0 and 3x+4y-12=0 . If the points P(alpha,0) and Q(0, beta) always lie on or inside the DeltaABC then

Delta ABC is formed by the lines 2x-3y-6=0,3x-y+3=0 and 3x+4y-12=0. If the points P(alpha,0) and Q(0,beta) always lie on or inside the Delta ABC then

A Delta ABC is formed by the lines 2x+3y-6=0 , x-2y=2 and 2x-y+2=0 .If the points P(alpha,0) and Q(0,beta) always lie on or inside the Delta ABC and the complete set of values of alpha, beta are A and B respectively then

A A B C is formed by the lines 2x-3y-6=0;3x-y+3=0a n d3x+4y-12=0. If the points P(alpha,0)a n dQ(0,beta) always lie on or inside the A B C , then: alpha in [-1,2]&beta in [-2,3] b.alpha in [-1,3]&beta in [-2,4] c. alpha in [-2,4]&beta in [-3,4] d. alpha in [-1,3]&beta in [-2,3]

A A B C is formed by the lines 2x-3y-6=0;3x-y+3=0a n d3x+4y-12=0. If the points P(alpha,0)a n dQ(0,beta) always lie on or inside the A B C , then: alpha in [-1,2]&beta in [-2,3] b. alpha in [-1,3]&beta in [-2,4] c. alpha in [-2,4]&beta in [-3,4] d. alpha in [-1,3]&beta in [-2,3]

Find the area of triangle formed by the lines: x+y-6=0,x-3y-2=0 and 5x-3y+2=0

Prove that the three lines 2x-y-5=0, 3x-y-6=0 and 4x-y-7=0 meet in a point.

The lines x-y-2=0, x+y-4=0 and x+3y=6 meet in the common point