According to the reaction
`C_(6)H_(6)+15//2O_(2)to3H_(2)O+6CO_(2)`
(`DeltaH=-3264.6 kJ // mol`) the energy evolved when `3.9g` of benzene is burnt in air will be

According to the equation, C_6H_6(l)+15/2O_2(g)rarr3H_2O(l)+6C_2(g) triangleH =-3264.4kJ/mol, the energy evolved when 7.8 g of benzene is burnt in air will be:

According to equation, C_(6)H_(6)(l)+15//2 O_(2)(g)rarr 6CO_(2)(g)+3H_(2)O(l), Delta H= -3264.4 "KJ mol"^(-1) the energy evolved when 7.8 g benzene is burnt in air will be -

According to equation, C_(6)H_(6)(l)+15//2 O_(2)(g)rarr 6CO_(2)(g)+3H_(2)O(l), Delta H= -3264.4 "KJ mol"^(-1) the energy evolved when 7.8 g benzene is burnt in air will be -

According to the equation C_(6)H_(6(l))+7/2 O_(2(g)) rarr 6CO_(2(g))+3H_(2)O_((l)), DeltaH=-xkJ The energy evolved when 3.9 gm of benzene is burnt in air is - 163.2 kJ heat of combustion of benzene is

The heat evolved in combustion of benzene is given by the following equation C_(6)H_(6)+15//2O_(2)to3H_(2)O+6CO_(2) : DeltaH=-3264.6 kJ Which of the following quantities of heat will be evolved when 39g of benzene are burnt in an open container ?

The heat evolved in combustion of benzene is given by the following equation : C_(6)H_(6)+15//2O_(2)to3H_(2)O+6CO_(2) : DeltaH=-3264.6 kJ Which of the following quantities of heat will be evolved when 39g of benzene are burnt in an open container ?

The heat evolved in combustion of benzene is given by the following equation : C_(6)H_(6)+15//2O_(2)to3H_(2)O+6CO_(2) : DeltaH=-3264.6 kJ Which of the following quantities of heat will be evolved when 39g of benzene are burnt in an open container ?

For the reaction C_(6)H_(12)(l)+9O_(2)(g)to6H_(2)O(l)+6CO_(2)(g) , DeltaH=-936.9kcal Which of the following is true ?

For the reaction C_(6)H_(12)(l)+9O_(2)(g)to6H_(2)O(l)+6CO_(2)(g) , DeltaH=-936.9kcal Which of the following is true ?

For the reaction C_(6)H_(12)(l)+9O_(2)(g)to6H_(2)O(l)+6CO_(2)(g) , DeltaH=-936.9kcal Which of the following is true ?