The weight of a body on the surface of moon is 1/6th of that on the Earth's surface. It is because acceleration due to gravit on the surface of moon is six times that on the surface of the Earth.

The gravitational force on the surface of th Moon is _______ times than that on the surface of the Earth.

The gravitational force on the surface of the Moon is_____________ times than that on the surface of the Earth.

The ratio of the mass of the moon to that of the earth is 1:81. If the radius of the moon is assumed to be one-fourth of that of the earth , then what is the acceleration due to gravity on the surface of the moon in terms of that on the earth's surface ? Hence, find the escape velocity from the surface of the moon in terms of that from the earth's surface.

The mass of the earth is 81 times that of the moon and the radius of the earth is 3.5 times that of the moon. The ratio of the acceleration due to gravity at the surface of the moon to that at the surface of the earth is

If a seconds pendulum is taken to the surface of the moon from the earth, its time period would be (acceleration due to gravity on the surface of the moon is 1/6 th that on the earth's surface)