`(1+secA)/(secA)=(sin^(2)A)/(1-cosA).`

Prove the following identity, where the angles involved are acute angles for which the expressions are defined. (iv) (1+secA)/(secA)=(sin^2A)/(1-cosA)

Prove the following identities, where the angles involved are acute angles for which the expressions are defined. : (1+secA)/(secA)=(sin^2A)/(1-cosA) .

(1+secA)/secA=(sin^2A)/(1-cosA)

Prove that (1+secA)/secA=sin^2A/(1-cosA) .

(cos2A)/(secA)+(sin2A)/(cosecA)=cosA

(cos2A)/(secA)+(sin2A)/(cosecA)=cosA

(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/(cosA)

Prove that (tanA+secA-1)/(tanA-secA+1)=(1+sinA)/(cosA) .

Prove that (tanA+secA-1)/(tanA-secA+1)=(1+sinA)/(cosA) .

(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/(cosA)