Define electric flux and write its SI unit . The electric field components in the figure shown are : `E_(x)=alphax,E_(y)=0,E_(z)=0` where `alpha=(100N)/(Cm)`.
Calculate the charge within the cube , assuming a = 0.1 m .

The electric components in the figure are E_(x)=alphax^(1//2) ,E_(y)=0,E_(z)=0 where alpha=800N//m^(2) if a=0.1m is the side of cube then the charge with in the cube is

The electric components in the figure are E_(x)=alphax^(1//2) ,E_(y)=0,E_(z)=0 where alpha=800N//m^(2) if a=0.1m is the side of cube then the charge with in the cube is

The electric field components in Figure are E_(x)=alpha x^(1/2), E_y=E_(z)=0 in which alpha=800 N//Cm^(1/2) . Calculate (a) the flux through the cube, and (b) the charge within the cube. Assume that a=0.1m.

The electric field components in Fig. are E_(x)=ax^(1//2), E_(y)=E_(z)=0 , in which alpha=800N//C m^(1//2) . Calculate the flux through the cube

The electric field components in figure are E_(x) =ax, E_(y) = E_(z) =0 in which a - 500 N/C m. Calculate (a) the flux through the cube and (b) the charge within the cube, length of side is a a=0.1 m

The electric field components in the figure below are E_(x) = 800 x^(2) N //C ,E_(y)= E_(z) = 0 . Calculate (1) The flux throught he cube and (2) The charge withing the cube Assume that a =0.1 m

(a) Define electric flux. Write its SI units. (b) The electric field components due to a charge inside the cube of side 0.1 m are as shown : E_(x)=alpha x, where alpha=500N//C-m E_(y)=0, E_(z)=0 . Calculate (i) the flux through the cube, and (ii) the charge inside the cube.

(a) Define electric flux. Write its SI units. (b) The electric field components due to a charge inside the cube of side 0.1 m are as shown : E_(x)=alpha x, where alpha=500N//C-m E_(y)=0, E_(z)=0 . Calculate (i) the flux through the cube, and (ii) the charge inside the cube.