Let `vecA,vecB,vecC`be unit vectors suppose that `vecA.vecB=vecA.vecC=0` and angle between `vecB` and `vecC` is `pi/6` then `vecA=k(vecBxxvecC)` and `k=`

Let vecA, vecB and vecC be unit vectors such that vecA.vecB = vecA.vecC=0 and the angle between vecB and vecC " be" pi//3 . Then vecA = +- 2(vecB xx vecC) .

Let vecA, vecB and vecC be unit vectors such that vecA.vecB = vecA.vecC=0 and the angle between vecB and vecC " be" pi//3 . Then vecA = +- 2(vecB xx vecC) .

If veca,vecb,vecc be unit vectors such that veca.vecb=veca.vecc=0 and the angle between vecb and vecc is pi//6 . Prove that veca=pm2(vecbxxvecc)

A class XII student appearing for a competitive examination was asked to attempt the following questions Let veca,vecb and vecc be three non zero vectors. Let veca,vecb and vecc be unit vectors such that veca.vecb=veca.vecc=0 and angle between vecb and vecc is pi/6 then veca=

vecA,vecB and vecC are unit vectors, vecA*vecB=vecA*vecC=0 , and the angle between vecB and vecC is 30^@ . Prove that, vecA=pm2(vecBxxvecC) .

Let veca, vecb and vecc be unit vectors such that veca.vecb=0 = veca.vecc . It the angle between vecb and vecc is pi/6 then find veca .

Let vea, vecb and vecc be unit vectors such that veca.vecb=0 = veca.vecc . It the angle between vecb and vecc is pi/6 then find veca .

Let vea, vecb and vecc be unit vectors such that veca.vecb=0 = veca.vecc . It the angle between vecb and vecc is pi/6 then find veca .

If veca,vecb and vecc are unit vectors such that veca+vecb+vecc=vec0 then angle between veca and vecb is

If veca,vecb and vecc are three unit vectors such that veca*vecb=veca*vecc=0 and angle between vecb and vecc is pi/6 , prove that veca=+-2(vecb xxvecc) .