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Refer to let DeltaU(1) and DeltaU(2) be ...

Refer to let `DeltaU_(1)` and `DeltaU_(2)` be the changes in internal energy in the system in process `A+B` and `DeltaW` be the net work done by the system in the process `A+B,

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Refer to figure. Let DeltaU_(1) and DeltaU_(2) be the changes in internal energy in the system in process A+B and DeltaW be the net work done by the system in the process A+B ,

Refer to figure. Let DeltaU_(1) and DeltaU_(2) be the changes in internal energy in the system in process A+B and DeltaW be the net work done by the system in the process A+B ,

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In given figure, let DeltaU_(1) and DeltaU_(2) be change in internal energy in process ABC and CDA respectively. DeltaQ and W be the net heta given and net work done by the system in the process ABC +CDA , then

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The change in internal energy DeltaU=0 in a cyclic process.

Refer to figure. Let and be the change in internal energy in processes A and B respectively, DeltaQ be the net heat given to the system in process A+B and DeltaW be the net work done by the system in the process A+B a) DeltaU_(1)+DeltaU_(2)=0 b) DeltaU_(1)-DeltaU_(2)=0 c) DeltaQ-DeltaW=0 d) DeltaQ+DeltaW_=0