[" (iii) "(1)/(x^(2))," (iv) "(x+1)/(x-1)]

Expand using binomial theorem: (i) (1-2x)^(4) " " (ii) (x+2y)^(5) (iii) (x-(1)/(x))^(6) " "(iv) ((2x)/(3)=(3)/(2x))^(5) (v) (x^(2) +(2)/(x))^(6)" "(vi) (1+(1)/(x^(2)))^(4)

If x=sqrt(2)+1 , then find the values of the following : (i)(1)/(x)" "(ii)x+(1)/(x)" "(iii)x-(1)/(x)" "(iv)x^(2)+(1)/(x^(2))

If x=sqrt(2)+1 , then find the values of the following : (i)(1)/(x)" "(ii)x+(1)/(x)" "(iii)x-(1)/(x)" "(iv)x^(2)+(1)/(x^(2))

Verify whether the values of x given in each case are the zeroes of the polynomial or not ? ….. (i) p(x)=2x+1,x=-(1)/(2) (ii) p(x)=5x-pi,x=(-3)/(2) (iii) p(x)=x^(2)-1,x =+-1 (iv) p(x)=(x-1)(x+2),x=-1,-2 (v) p(y)=y^(2),y=0 (vi) p(x)=ax+b,x=-(b)/(a)

If x=3+2sqrt(2) , then find : (i)(1)/(x)" "(ii)x+(1)/(x)" "(iii)x-(1)/(x)" "(iv)x^(2)-(1)/(x^(2))

If x=3+2sqrt(2) , then find : (i)(1)/(x)" "(ii)x+(1)/(x)" "(iii)x-(1)/(x)" "(iv)x^(2)-(1)/(x^(2))

If x=2+sqrt(3) , then find : (i)(1)/(x)" "(ii)x+(1)/(x)" "(iii)x-(1)/(x)" "(iv)x^(2)+(1)/(x^(2))

If x=2+sqrt(3) , then find : (i)(1)/(x)" "(ii)x+(1)/(x)" "(iii)x-(1)/(x)" "(iv)x^(2)+(1)/(x^(2))

If graph of y=(x-1)(x-2) is then draw the graph of the following (i) y=|(x-1)(x-2)| (ii) |y|=(x-1)(x-2) (iii) y=(|x|-1)(|x|-2) (iv) |(|x|-1)(|x|-2)| (v) |y|=|(|x|-1)(|x|-2)|

If x=3+2sqrt(2) , find : (i) (1)/(x) (ii) x-(1)/(x) (iii) (x-(1)/(x))^(3) (iv)x^(3)-(1)/(x^(3))