Home
Class 12
PHYSICS
A series LCR circuit is made by taking ...

A series LCR circuit is made by taking
`R = 100 Omega, L = (2)/(pi)` and `C = (100)/(pi) mu F`. The
series combination is connected across an a.c. source of 220 V, 50 Hz. Calculate impedance of the circuit and peak value of current flowing n the circuit. What is power factor of the circuit ?
Compare it with one at resonance frequency.

Promotional Banner

Similar Questions

Explore conceptually related problems

In an LCR series combination, R=400 Omega , L=100 mH and C= 1muF . This combination is connected to a 25sin2000t volt voltage source. Find the impedance of the circuit and the peak value of the circuit current.

Ann ac source of 100 V, 50 Hz is connected across a 20 Omega resistor and 2 mH inductor in series. Calculate (a) Impedance of the circuit (b) r.m.s value of current in the circuit.

An LCR series circuit consists L = 80 mH, C = 60 muF and R = 15Omega . The combination is connected to a 230 V, 50 Hz AC supply. Calculate the impedance in the circuit.

A series LCR circuit is connected to a variable frequency 230 V source , L=5.0 H, C=80muF,R=40Omega Obtain impedance of the circuit and aplitude of current at resonance.

A 1 mu F capacitor is connected to a 220 V, 50 Hz a.c. source. Find the virtual value of current through the circuit if a resistor of 100 Omega is connected in series with the capacitor.

In a series RC circuit connected across an AC source of 220 V 50 Hz calculate the rms voltage across resistor and capacitor if values of R and C are 100 Omega and 20 μF respectively .

A 10 mu F capacitor is in series with a 50 Omega resistance and the combination is connected to a 220 V, 50 Hz line. Calculate (i) the capacitive reactance, (ii) the impedance of the circuit and (iii) the current in the circuit.