A simple pendulum is constructed by hanging a heavy ball by a 5.0 long string. It undergoes small oscillation. a. How many oscillations does it make per second? b. What will be the frequency if the system is taken on the moon where acceleration due to gravitation of the moon is `1.67 ms^-2?`

A simple pendulum is constructed by hanging a heavy ball by a 5.0 m long string. It undergoes small oscillation. a. How many oscillations does it make per second? b. What will be the frequency if the system is taken on the moon where acceleration due to gravitation of the moon is 1.67 ms^-2?

What would be the time period of a seconds pendulum constructed on the earth if it is taken to the surface of the moon. The acceleration due to gravity on the surface of the moon is 1//6g_("earth")

The seconds hand of pendulum clock (P) and that of a clock working based on spring oscilations (S) tick 60 divisions in one minute on earth. If the two clocks are taken to the moon, where the acceleration due to gravity is (1/5. 76)th that on the earth, the number of divisions ticked by P and S respectively in an actual time of 1 minute will be

A vertical spring mass system has the same time period as simple pendulum undergoing small oscillations. Now, both of them are put in an elevator going downwards with an acceleration 5 m//s^(2) . The ratio of time period of the spring mass system to the time period of the pendulum is (Assume, acceleration due to gravity, g=10 m//s^(2) )

Find the acceleration due to gravity on the surface of the moon by taking a seconds pendulum from the earth's surface. Arrange the following steps in sequential order to solvbe the above problem. (A) Find the time period of this simple pendulum on the surface of the moon using a stop clock [ T_(M)] (B) The acceleration due to gravity on the moon (gm) is 1/6th the accleration due to gravity on the earth (ge). (C) Use the formula , T = 2 pi sqrt(l/g) (D) first , take pendulum to the surface of the moon without altering the length of the pendulum (l), . (E) Substibe the value of T_(M) in (a), then (T_(E))/(T_(M)) sqrt ((g_(M))/(g_(E)) , and obtain the value of (g_(m))

Two bodies A and B of masses 50 kg and 100 kg are kept at a distance of 2 m on the surface of the earth. The gravitational force of attraction between them is F. A and B are then taken to the moon and are kept at the same distance of 2 m. The acceleration due to gravity on the surface of the moon =(g)/(6) , where g is the acceleration due to gravity on the earth. What will be the gravitational force of attraction between A and B on the surface of the moon ?

A simple pendulum with a bob of mass 40g and charge +2mu C makes 20 oscillation in 44 s. A vertical electric field magnitude 4.2xx10^(4) NC^(-1) pointing downward is applied. The time taken by the pendulum to make 15 oscillation in the electric field is (acceleration due to gravity =10 ms^(-2) )