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Calculate the amount of energy released ...

Calculate the amount of energy released during the `alpha`-decay of
`._(92)^(238)Urarr_(90)^(234)Th+._(2)^(4)He`
Given: atomic mass of `._(92)^(238)U=238.05079 u`, atomic mass of `._(90)^(234)Th=234.04363 u`,
atomic mass `._(2)^(4)He=4.00260u , 1u=931.5 MeV//c^(2)`. Is this decay spontaneous?Give reason.

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Calculate the energy released in MeV in the following nuclear reaction : ._(92)^(238)Urarr._(90)^(234)Th+._(2)^(4)He+Q ["Mass of "._(92)^(238)U=238.05079 u Mass of ._(90)^(238)Th=234.043630 u Massof ._(2)^(4)He=4.002600 u 1u = 931.5 MeV//c^(2)]

Calculate the energy released in MeV in the following nuclear reaction : ._(92)^(238)Urarr._(90)^(234)Th+._(2)^(4)He+Q ["Mass of "._(92)^(238)U=238.05079 u Mass of ._(90)^(238)Th=234.043630 u Massof ._(2)^(4)He=4.002600 u 1u = 931.5 MeV//c^(2)]

The partlcles emitted 1n the decay of ""_(92)^(238)U to ""_(92)^(234)U

Find energy released in the alpha decay, Given _92^238Urarr_90^234Th+_2^4He M( _92^238U)=238.050784u M( _90^234Th)=234.043593u M( _2^4He)=4.002602u

Find energy released in the alpha decay, Given _92^238Urarr_90^234Th+_2^4He M( _92^238U)=238.050784u M( _90^234Th)=234.043593u M( _2^4He)=4.002602u

Alpha decay of ._(92)^(238)U forms ._(90)^(234)Th . What kind of decay from ._(90)^(234)Th produces ._(84)^(234)Ac ?