When two progressive waves `y_(1) = 4 sin (2x - 6t)` and `y_(2) = 3 sin (2x - 6t - (pi)/(2))` are superimposed, the amplitude of the resultant wave is

When two progressive waves y_(1) = 4 sin (2 x - 6t) and y_(2) = 3 sin (2x - 6t -(pi)/(2)) are superposed, the amplitude of the resultant wave is

Two progressive waves having equation x_(1) = 3 sin omegatau and x_(2) = 4 sin (omegatau + 90^(@)) are superimposed. The amplitude of the resultant wave is

Equations of two light waves are y_(1) = 4 sin omega t and y_(2) = 3 sin (omega t + (pi)/(2)) . What is the amplitude of the resultant wave as they superpose on each other?

The equations for displacement of two light waves forming interference pattern are y_(1) = 4 sin omega t and y_(2) =3 sin (omega t+ (pi)/(2)) . Determine the amplitude of the resultant wave.