Equation of motion for a particle performing damped harmonic oscillation is given as `x=e^(-1t) cos(10pit+phi)`. The time when amplitude will half of the initial is :

Equation of motion for a particle performing damped harmonic oscillation is given as x=e^(-0.1t) cos(10pit+phi) . The time when amplitude will half of the initial is :

The equation of a simple harmonic motion is given by , x=8sin(8pit)+6cos(8pit) . The initial phase angle is

The equation of a simple harmonic motion is given by , x=8sin(8pit)+6cos(8pit) . The initial phase angle is

The amplitude of a particle in damped oscillation is given by A=A_0e^(-kt) where symbols have usual meanings if at time t=4s,the amplitude is half of initial amplitude then the amplitude is 1/8 of initial value t=

The displacement of a damped harmonic oscillator is given by x(t)=e^(-0.1t)cos(10pit+phi) . Here t is in seconds The time taken for its amplitude of vibration to drop to half of its initial is close to :

A simple harmonic motion is given by y = 5(sin3pit + sqrt(3) cos3pit) . What is the amplitude of motion if y is in m ?

The displacement of a damped harmonic oscillator is given by x(t)-e^(-0.1t) cos(10pit+varphi) .Here t is in seconds. The time taken for its amplitude of vibration to drop to half of its initial value is close to :

The displacement of a particle executing simple harmonic motion is given by y = 4 sin(2t + phi) . The period of oscillation is

A simple harmonic motion is given by the equation x=10cos 10 pit . The phase of S.H.M. after time 2 s is

A simple harmonic motion is given by the equation x=10cos 10 pit . The phase of S.H.M. after time 2 s is