The value of `C_(p) - C_(v)` is `1.09R` for a gas sample in state `A` and is `1.00R` in state `B`. Let `A_(A),T_(B)` denote the temperature and `p_(A)` and `P_(B)` denote the pressure of the states `A` and `B` respectively. Then

The value of C_(p) - C_(v) is 1.09R for a gas sample in state A and is 1.00R in state B . Let T_(A),T_(B) denote the temperature and p_(A) and p_(B) denote the pressure of the states A and B respectively. Then

The value of (C_p - C_v) is 1.00 R for a gas sample in state A and is 1.08 R in state B. Let ( p_A, p_B) denote the pressures and (T_A and T_B) denote the temperatures of the states A and B respectively . Most likely

The value of C_(P) - C_(v) = 1.00 R for a gas in state A and C_(P) - C_(v) = 1.06 R in another state. If P_(A) and P_(B) denote the pressure and T_(A) and T_(B) denote the temperature in the two states, then

The value of C_(P) - C_(v) = 1.00 R for a gas in state A and C_(P) - C_(v) = 1.06 R in another state. If P_(A) and P_(B) denote the pressure and T_(A) and T_(B) denote the temperature in the two states, then

An experiment is being performed by a student in laboratory on ideal gas. He found the value of C_P-C_V equal to 1.00 R in state A and is 1.08 R in state B.. Let P_A, P_B denote the pressures and T_A, T_B denote the temperature of state A and B respectively. Which of the following will be correct?

For a gas C_(P)-C_(V)=R in a state P and C_(P)-C_(V)=1.10 R in a state Q, T_(P) and T_(Q) are the temperatures in two different states P and Q respectively. Then

A capillary tube is dipped in a liquid. Let pressure at point A,B and C be p_(A)p_(B) and p_(C) respectively, then

In the P - V diagram, the point B and C correspond to temperatures T _(1) and T_(2) respectively. State relationship between T_(1) and T_(2).

One mole of a gas is in state A[P, V, T_(A)] . A small adiabatic process causes the state of the gas to change to B [P + dP, V + dV, T_(B)] . The changes dV & dP are infinitesimally small and dV is negative. An alternative process takes the gas from state A to B via A rarr C rarr B . A rarr C is isochoric and C rarr B is isobaric path. State at C is [P + dP, V, T_(C)] . (a) Rank the temperatures T_(A), T_(B) and T_(C) from highest to lowest. (b) Find g of the gas in terms of T_(A) , T_(B) and T_(C) .