Equation of normal of ellipse

Equation of normal to the ellipse at (x_(1);y_(1))

Find the equation of normal to the ellipse x^(2)+4y^(2)=4 at (2cos theta,sin theta). Hence,find the equation of normal to this ellipse which is parallel to the line 8x+3y=0.

Find the equation of normal to the ellipse x^(2)+4y^(2)=4 at (2 cos theta, sin theta) . Hence find the equation of normal to this ellipse which is paralel to the line 8x+3y=0 .

The equation of normal to the ellipse 4x^2 +9y^2 = 72 at point (3,2) is:

The equation of normal to the ellipse 4x^(2)+9y^(2)=72 at point (3,2) is:

The equation of normal to the ellipse x^(2)+4y^(2)=9 at the point wherr ithe eccentric angle is pi//4 is

The equation of normal to the ellipse x^(2)+4y^(2)=9 at the point wherr ithe eccentric angle is pi//4 is

Find the equation of normal to the ellipse (x^(2))/(16)+(y^(2))/(9) = 1 at the point whose eccentric angle theta=(pi)/(6)

Find the equation of normal to the ellipse (x^(2))/(16)+(y^(2))/(9) = 1 at the point whose eccentric angle theta=(pi)/(6)