If one root of the equation `ax^2+bx+c=0` is the square of the other, prove that `b^3+ac^2+a^2c =3abc`.

If one root of the equation ax^(2)+bx+c=0 is the square of the other,then

If one root of the equation ax^(2)+bx+c=0 is the square of the other,then

Q.If one root of the equation ax^(2)+bx+c=0 is square of the other then

If one root of the equation ax^2+bx+c=0 is square the other root, then prove that b^3+ac^2+a^2c= 3abc .

If one root of the equation ax^2+bx+c=0 is the cube of the other, prove that , (b^2-2ca)^2=ca(c+a)^2

If one root of the equation ax^2+bx+c=0 be the square of the other and b^3+a^2c+ac^2=kabc then k=

If one root of the equation ax^(2)+bx+c=0 be the square of the other, and b^(3)+a^(2) c+ac^(2)=kabc , then the value of k is

If one root of the equation ax^2+bx+c=0 be the square of the other,and b^3+ a^(2)c+ac^(2)= kabc then the value of k is

If one root of the equation ax^(2)+bx+c=0 is the square of the other than a(c-b)^(3)=cX where X is