The equation `14x^2 - 4xy+ 11y^2 - 44x - 58y + 71 = 0` represents

To remove the x and y terms of the equation 14x^(2) - 4xy + 11y^(2) - 36 + 48 y + 41 = 0 the shifted origin is

Show that the equation 2x^(2) + xy - y^(2) + x + 4y - 3 = 0 represents a pair of lines.

Find the centre of the conic 14x^(2) - 4xy + 11y^(2) - 44x - 58y +71=0

The equation x^(2) + 4xy + 4y ^(2) - 3x - 6 = 0 represents

The centre of the conic 14x^(2)-4xy+11y^(2)-44x-58y+71=0, is

The centre of the conic 14x^(2)-4xy+11y^(2)-44x-58y+71=0, is