The `X`- ray wavelength of `L_(alpha)` line of platinum `(Z = 78)` is `1.30 Å`. The `X` - ray wavelength of `L_(alpha)` line of Molybdenum `(Z = 42)` is

The X-ray wavelength of L_(a) line of platinum (Z=78) is 1:30 Å.The X-ray wavelength of L_(a) line of Molybdeum (Z=42) is

The K_(alpha) line obtained for molybdenum (Z = 42) is 0.71 Å. Then, the wavelength of the K_(alpha) line of copper (Z = 29) is

The K_(alpha) line obtained for molybdenum (Z = 42) is 0.71 Å. Then, the wavelength of the K_(alpha) line of copper (Z = 29) is

The wavelength of the characteristic X-ray K_(alpha) line emitted from Zine (Z = 30) is 1.415 Å . Find the wavelength of the K_(alpha) line emitted from molybdenum Z = 42) .

The wavelength of the characteristic X-ray K_(alpha) line emitted from Zine (Z = 30) is 1.415 Å . Find the wavelength of the K_(alpha) line emitted from molybdenum Z = 42) .

If lambda_(Cu) is the wavelength of K_(alpha) X-ray line of copper (atomic number 29 ) and lambda_(Mo) is the wavelength of the K_(alpha) X-ray line of molybdenum (atomic number 42 ),then the ratio lambda_(Cu)//lambda_(Mo) is close to

If lambda_(Cu) is the wavelength of K_(alpha) X-ray line of copper (atomic number 29 ) and lambda_(Mo) is the wavelength of the K_(alpha) X-ray line of molybdenum (atomic number 42 ),then the ratio lambda_(Cu)//lambda_(Mo) is close to

The wavelength of L_alpha line in X-ray spectrum of ._76Pt is 1.32Å. The wavelength of L_alpha line in X-ray spectrum of another unknown element is 4.17Å. If screening constant for L_alpha line is 7.4, then atomic number of the unknown element is

The wavelength of k_alpha line in the X-ray spectrum for tungsten (Z=74) is 200 Å. What would be the wavelength of same line for platinum Z =78 ?

The wavelength of k_alpha line in the X-ray spectrum for tungsten (Z=74) is 200 Å. What would be the wavelength of same line for platinum Z =78 ?