Make a rough sketch of the region given below and find its area using integration `{(x,y): 0 leq y leq x^2+3,0 leq y leq 2x+3,0 leq x leq 3}`.

Make a rough sketch of the region given below and find its area, using integration : {(x,y):y^2le4x,4x^2+4y^2le9}

Make a rough sketch of the region given below and find its area using integration {(x,y):0<=y<=x^(2)+3,0<=y<=2x+3,0<=x<=3}

The area of the region included between the regions satisfying min(|x|,|y|) geq1 and x^2+y^2leq5 is

The area of the region included between the regions satisfying min(|x|,|y|) geq1 and x^2+y^2leq5 is

If p, q, r and s are positive real numbers such that p+ q + r + s = 2 , then M=(p+q)(r+s) satisfies the relation, when (A) 0 lt M leq 1 (B) 1 leq M leq 2 .(C) 2 leq M leq 3 (D) 3 leq M leq 4

Let f(x)=1+x , 0 leq x leq 2 and f(x)=3−x , 2 lt x leq 3 . Find f(f(x)) .

The slope of the tangent to the curve y=e^x cosx is minimum at x= a,0 leq a leq 2pi , then the value of a is

Draw a rough sketch of the given curve y=1+abs(x+1),x=-3, x-=3, y=0 and find the area of the region bounded by them, using integration.

Draw a rough sketch of the given curve y=1+abs(x+1),x=-3, x-=3, y=0 and find the area of the region bounded by them, using integration.

Draw a rough sketch of the given curve y=1+abs(x+1),x=-3, x=3, y=0 and find the area of the region bounded by them, using integration.