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If arithmetic mean of two positive numbe...

If arithmetic mean of two positive numbers is A, their geometric mean is G and harmonic mean H, then H is equal to

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The arithmetic mean of two positive numbers is 6 and their geometric mean G and harmonic mean H satisfy the relation G^(2)+3H=48 . Then the product of the two numbers is

The arithmetic mean of two positive numbers is 6 and their geometric mean G and harmonic mean H satisfy the relation G^(2)+3H=48 . Then the product of the two numbers is

The arithmetic mean of two positive numbers is 6 and their geometric mean G and harmonic mean H satisfy the relation G^(2)+3H=48 . Then the product of the two numbers is

The arithmetic mean of two positive numbers is 6 and their geometric mean G and harmonic mean H satisfy the relation G^(2)+3H=48 . Then the product of the two numbers is

The geometric mean G of two positive numbers is 6 . Their arithmetic mean A and harmonic mean H satisfy the equation 90A+5H=918 , then A may be equal to:

The geometric mean G of two positive numbers is 6 . Their arithmetic mean A and harmonic mean H satisfy the equation 90A+5H=918 , then A may be equal to:

The geometric mean G of two positive numbers is 6 . Their arithmetic mean A and harmonic mean H satisfy the equation 90A+5H=918 , then A may be equal to:

The arithmetic mean of two numbers is 6 and their geometric mean G and harmonic mean H satisfy the relation G^2+3H=48 .Find the two numbers.