A particle executes SHM with time period 8 s. Initially, it is at its mean position. The ratio of distance travelled by it in the 1st second to that in the 2nd second is

Time period of a particle executing SHM is 8 sec. At t=0 it is at the mean position. The ratio of the distance covered by the particle in the 1st second to the 2nd second is:

Time period of a particle executing SHM is 8 sec. At t=0 it is at the mean position. The ratio of the distance covered by the particle in the 1st second to the 2nd second is:

A particle executes SHM with a time period of 8 s. It is starts from the extreme position at time t = 0, the ratio of distances covered by it in 1st and 2nd seconds is

A particle executes SHM with a time period of 8 s . If it starts from the extreme position at time t = 0 , the ratio of distance covered by it in 1st and 2nd seconds is

The period of a particle in SHM is 8s . At t=0 it is at the mean position. The ratio of the distances traveled by it in the first and the second second is

The time period of a simple harmonic motion is 8 s At t=0. it is at the mean position.The ratio of the distance travelled bi it in the first and second seconds is,