A physical pendulum is positioned so that its centre of gravity is above the suspension point. When the pendulum is realsed it passes the point of stable equilibrium with an angular velocity `omega`. The period of small oscollations of the pendulum is

A particle pendulum is positioned such that is centre of gravity is vertically above suspension point. From that position the pendulum started moving tward the stable equilibroum and passed it with an angular velocity omega . By neglecting the friction at point of suspension, the period of small oscillations of the pendulum is

When the point of suspendion of pendulum is moved, its period of oscillation

When the point of suspendion of pendulum is moved, its period of oscillation

Two identical simple pendulums each of length 'l' are connected by a weightless spring as shown. In equilibrium, the pendulums are vertical and the spring is horizontal and undformed. The time period of small oscillations of the linked pendulums, when they are deflected form their equilibrium positive through equal displacements in the same vertical plane in the opposite directions and released, is

(A) : Simple pendulum is said to be executing linear SHM if its angular amplitude is small (R) : Time period of simple pendulum depends on mass of the pendulum bob.

The time -period of a simple pendulum is 2s and its can go to and fro from equilibrium position at a maximum distance of 5 cm. if at the start of the motion the pendulum is the position of maximum displacements towars the right of the equilibrium position, then write the displacement equation of the pendulum.

In physical pendulum, the time period for small oscillation is given by T=2pisqrt((I)/(Mgd)) where I is the moment of inertial of the body about an axis passing through a pivoted point O and perpendicular to the plane of oscillation and d is the separation point between centre of gravity and the pivoted point. In the physical pendulum a speacial point exists where if we concentrate the entire mass of body, the resulting simple pendulum (w.r.t. pivot point O) will have the same time period as that of physical pendulum This point is termed centre of oscillation. T=2pisqrt((I)/(Mgd))=2pisqrt((L)/(g)) Moreover, this point possesses two other important remarkable properties: Property I: Time period of physical pendulum about the centre of oscillation (if it would be pivoted) is same as in the original case. Property II: If an impulse is applied at the centre of oscillatioin in the plane of oscillation, the effect of this impulse at pivoted point is zero. Because of this property, this point is also known as the centre of percussion. From the given information answer the following question: Q. A uniform rod of mass M and length L is pivoted about point O as shown in Figgt It is slightly rotated from its mean position so that it performs angular simple harmonic motion. For this physical pendulum, determine the time period oscillation.