56. Match the interval(s) of x, for which fx) is real Column-4 Column-l (A) 2x + 2/(x) = 2 V1012-- 1012 1-5K 7X-7 (D) (x)-./(x2-3x-10)(In(X-3),-d) T Space for Rough Work

The integral value of real x for which : (5x-1) lt (x+1)^(2) lt (7x-3) is :

If x is real, tehn range of (3x -2)/(7x+5) is :

If x is real, then range of (3x -2)/(7x+5) is :

Simplify : 7x + 3x(x-4) = ? A. 10x + 12 B. 10x - 12 C. 3x^(2) + 5x D. 3x^(2) - 5x

{:("Column A" , "A function f(x) is defined for all real numbers as","Column B"),(, f(x)=(x - 1)(x-2)(x-3)(x-4),),( f(2.5), ,f(3.5)):}

Let f(x) = |x -1| + |x-2| + |x-3| , match the column I for the value of k column II. {:("Column - I" , " Column -II"),("(A) f(x) = k has no solution " ,"(p) 1 " ),("(B) f(x)=k has only one solution" , "(q) 2"),(" (C) f(x) = k has two solution of same sign " , "(r) 4"),("(D) f(x)= k has two solution of opposite sign" , "(s) 5"),(,"(t) 8"):}

Let f(x) = |x -1| + |x-2| + |x-3| , match the column I for the value of k column II. {:("Column - I" , " Column -II"),("(A) f(x) = k has no solution " ,"(p) 1 " ),("(B) f(x)=k has only one solution" , "(q) 2"),(" (C) f(x) = k has two solution of same sign " , "(r) 4"),("(D) f(x)= k has two solution of opposite sign" , "(s) 5"),(,"(t) 8"):}

Solve the inequalities given below for real x :- x/4< ((5x-2))/3-((7x-3))/5

{:("Column A", x + y=7 and x^2 + y^2 = 25 , "Column B"),(x+y^2,,3 + 4^2):}