ABCD is a parallelogram. X and Y are mid-points of BC and CD. Prove that `ar(triangleAXY)=3/8ar(||^[gm] ABCD)`

ABCD is parallelogram. X and Y are the mid-points of BC and CD respectively. Prove that ar (DeltaAXY) =3/8 ar (||)^(gm) ABCD .

ABCD is parallelogram. X and Y are the mid-points of BC and CD respectively. Prove that ar (DeltaAXY) =3/8 ar (||gm ABCD) .

In the given figure, ABCD is a parallelogram. E and F are any two points on AB and BC, respectively. Prove that ar (triangleADF)=ar(triangleDCE) .

ABCD is a parallelogram, E and F are the mid-points of BC and CD. Find the ratio of area of parallelogram ABCD and DeltaAEF

In the adjoining figure, ABCD is a parallelogram and P is any points on BC. Prove that ar(triangleABP)+ar(triangleDPC)=ar(trianglePDA) .

In the figure. ABCD is a parallelogram and O is any point on BC . Prove that ar (triangleABO) + ar (triangleDOC) = ar(triangleODA)

ABCD is a parallelogram and O is a point in its interior. Prove that (i) ar(triangleAOB)+ar(triangleCOD) =(1)/(2)ar("||gm ABCD"). (ii) ar(triangleAOB)+ar(triangleCOD)=ar(triangleAOD)+ar(triangleBOC) .

In the adjoining figure, ABCD is a parallelogram. Points P and Q on BC trisect BC. Prove that ar(triangleAPQ)=ar(triangleDPQ)=(1)/(6)ar(triangleABCD) .

Given a parallelogram ABCD where X and Y are the mid-points of the sides BC and CD respectively . Prove that: ar (Delta AXY) = (3)/(8) xx ar (//gm) ABCD

ABCD is a parallelogram and a line through A meets DC at P and BC (produced) at Q. Prove that ar(triangleBPC) = ar(triangleDPQ)