If `theta_1 and theta_2` are the angles made by the lines `(x^2 +y^2)(cos^2theta sin^2 theta+sin^2theta)=(x tan alpha-y sin theta)^2` with positive axis of x in the anti-clock wise direction, if `theta=pi/6, tan theta_1 + tan theta_2` equals

If theta_(2) and theta_(2) are the angles made by the lines (x^(2)+y^(2))(cos^(2) theta sin^(2) alpha+ sin^(2) theta)= (x tan alpha- y sin theta)^(2) with positive axis of x in the anticlock wise direction, if theta=(pi)/(6), tan theta_(1)+ tan theta_(2) , equals

If cos^2theta-sin^2 theta = 1/2 . Then tan theta =

(1+sin2 theta-cos2 theta)/(1+sin2 theta+cos2 theta)=tan theta

Find the value of tan ^2theta sin^2 theta+ sin^2 theta-tan^2theta-1 =0

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

The difference of the tangents of the angles which the lines x^(2)(sec^(2) theta - sin^(2) theta)-2xy tan theta+y^(2)sin^(2) theta=0 makes with x axis is

Prove that (1+sin2 theta)/(1-sin2 theta)=((1+tan theta)/(1-tan theta))^(2)

Prove that (1+sin2 theta)/(1-sin2 theta)=((1+tan theta)/(1-tan theta))^(2)

Prove: (cos^2theta)/(1-tan theta) + (sin^3 theta)/(sin theta - cos theta ) = 1 + sin theta cos theta