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If the vectors `vec a` and `vec b`are linearly independent and satisfying `(sqrt3tantheta-1)vec a + (sqrt3sectheta-2)vec b=vec 0`,then the most general values of `theta` are:

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As these vectors are linearly independent, there coefficient will be `0`.
`:. sqrt3tantheta +1 = 0 =>tan theta = -1/sqrt3`
`sqrt3sec theta -2 = 0 => sec theta = 2/sqrt3`
As `tan theta` is negative and ` sec theta` is positiive, `theta` will lie in fourth quadrant.
`:. tan theta = -1/sqrt3 => theta = 2pi -pi/6`
`sec theta = 2/sqrt3 => theta = 2pi-pi/6`
General value of `theta = 2npi-pi/6`
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