In a `DeltaABC`, `A=(2pi)/3, b-c=3sqrt3 cm` and `area(DeltaABC)=(9sqrt3)/2 cm^2`. Then `a` is

In DeltaABC, A=(2pi)/(3), b-c=3sqrt3 cm and are (DeltaABC) =(9sqrt3)/(2) cm^(2). Solve for side a.

In DeltaABC, A=(2pi)/(3),b-c=3 sqrt(3) cm and area of DeltaABC=(9 sqrt(3))/(2)cm^(2) . Then BC=

In DeltaABC, A = (2pi)/(3), b -c = 3 sqrt3 cm and " area of " Delta ABC = (9sqrt3)/(2) cm^(2) , then BC =

In DeltaABC, A = (2pi)/(3), b -c = 3 sqrt3 cm and " area of " Delta ABC = (9sqrt3)/(2) cm^(2) , then BC =

In DeltaABC, A = (2pi)/(3), b -c = 3 sqrt3 cm and " area of " Delta ABC = (9sqrt3)/(2) cm^(2) , then a =

In a A B C ,A=(2pi)/3,b-c=3sqrt(3)c m and area ( A B C)=(9sqrt(3))/2c m^2dot then ' a ' is

If in Delta ABC, b-c = 3sqrt3 , A= 120 ^(@) and the area of Delta ABC = (9sqrt3)/( 2) sq. cm, then a=

In a DeltaABC , if a = 3, b=2sqrt(3) and c=sqrt(3) , then A=

In a DeltaABC , if a = 3, b=2sqrt(3) and c=sqrt(3) , then A=

In a DeltaABC, If A=30^@,b=2,c=sqrt3+1, then (C-B)/2 is