Let `f : R -> R` be defined as `f(x) = x^3 + 3x^2 + 6x-5 + 4e^(2x) and g(x)= f^-1(x)`, then find `g' (-1)`.

Let f:R rarr R be defined as f(x)=(2x-3 pi)^(2)+(4)/(3)x+cos x and g(x)=f'(x) , then find g(x)

Let f : R rarr R be defined by f(x) = 3x^2-5 and g : R rarr R by g(x) = (x)/(x^2+1) xx Then gof is

Let f:R rarr R defined by f(x)=x^(3)+e^((x/2)) and let g(x)=f^(-1)(x) then the value of g'(1) is

Let f:R rarr R defined by f(x)=x^(3)+e^(x/2) and let g(x)=f^(-1)(x) then the value of g'(1) is

Let f : R - {2} rarr R be defined as f(x) = (x^2 - 4)/(x-2) and g: R rarr R be defined by g(x) = x + 2. Find whether f = g or not.

If f : R to R , g : R to R are defined by f (x) = 4x - 1 and g (x) = x ^(2) + 2 then find (gof) (x)

If f : R to R , g : R to R are defined by f (x) = 4x - 1 and g (x) = x ^(2) + 2 then find (fof) (x)

Let f :R to R be fefined as f(x) = 2x -1 and g : R - {1} to R be defined as g(x) = (x-1/2)/(x-1) Then the composition function ƒ(g(x)) is :