Home
Class 12
CHEMISTRY
Relative decrease in vapour pressure of ...

Relative decrease in vapour pressure of an aqueous `NaCl` is `0.167`. Number of moles of `NaCl` present in `180g` of `H_(2)O` is:

Promotional Banner

Similar Questions

Explore conceptually related problems

Relative decrease in vapour pressure of an aqueous NaCl is 0.181. Number of moles of NaCl present in 180g of H_2O is (consider 100% dissociation of NaCl)

Relative decrease in vapour pressure in vapour pressure of an aqueous solution NaCI is 0.1067, Number of moles of NaCI present in 180 g H_(2)O is:

Relative lowering in vapour pressure of an aqueous NaCl solution is 1/6. What is the number of moles of NaCl present in 180g H_(2)O

Relative decrease in vapour pressure of an aqueous solution containing 2 moles [Cu(NH_(3))_(3)Cl]Cl in 3 moles H_(2)O is 0.50. on reaction with AgNO_(3) , this solution will from

Relative decrease in vapour pressure of an aqueous solution containing 2 moles [Cu(NH_3)_3Cl] Cl in 3 moles H_2O is 0.50. On reaction with AgNO_3 this solution will form (assuming no change in degree of ionisation of substance on adding AgNO_3 ).

The relative decreases in the vapour pressure of an aqueous solution containing 2 mol [Cu(NH_(3))_(3)Cl]Cl in 3 mol H_(2)O is 0.50 . On reaction with AgNO_(3) , this solution will form

The relative decreases in the vapour pressure of an aqueous solution containing 2 mol [Cu(NH_(3)_(3)Cl] in 3 mol H_(2)O is 0.50 . On reaction with AgNO_(3) , this solution will form

The relative decreases in the vapour pressure of an aqueous solution containing 2 mol [Cu(NH_(3)_(3)Cl] in 3 mol H_(2)O is 0.50 . On reaction with AgNO_(3) , this solution will form