The line which passes through the origin and intersect the two lines `(x-1)/2 = (y+3)/4 = (z-5)/3 and (x-4)/2 = (y+3)/2 = (z-14)/4` is :

The equation of the plane which passes through the point of intersection of lines (x-1)/(3)=(y-2)/(1)=(z-3)/(2), and (x-3)/(1)=(y-1)/(2)=(z-2)/(3) and at greatest distance from point (0,0,0) is a.4x+3y+5z=25 b.4x+3y=5z=50c3x+4y+5z=49d.x+7y-5z=2

The equation of the plane which passes through the point of intersection of lines ""(x-1)/3=(y-2)/1=(z-3)/2"","and"(x-3)/1=(y-1)/2=(z-2)/3 and at greatest distance from point (0,0,0) is a. 4x+3y+5z=25 b. 4x+3y=5z=50 c. 3x+4y+5z=49 d. x+7y-5z=2

The equation of the plane which passes through the point of intersection of lines ""(x-1)/3=(y-2)/1=(z-3)/2"","and"(x-3)/1=(y-1)/2=(z-2)/3 and at greatest distance from point (0,0,0) is a. 4x+3y+5z=25 b. 4x+3y=5z=50 c. 3x+4y+5z=49 d. x+7y-5z=2

The point of intersection of lines (x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-4)/(5)=(y-1)/(2)=(z)/(1) is

" The point of intersection of lines "(x-1)/(2)=(y-2)/(3)=(z-3)/(4)" and "(x-4)/(5)=(y-1)/(2)=(z)/(1)" is "

The equation of the plane passing through the origin and containing the line (x-1)/5=(y-2)/4=(z-3)/5 is

Find the point of intersection of the lines (x-1)/(2)=(y-2)/(3)=(z-3)/(4) and (x-4)/(5)=(y-1)/(2)=z .