A body of mass 0.01 kg executes simple harmonic motion about x = 0 under the influence of a force as shown in figure. The time period of SHM is

A body of mass 0.01 kg executes simple harmonic motion (SHM) about x=0 under the influence of a force shown in the figure. The period of the SHM is

A body of mass 0.01 kg executes simple harmonic motion (SHM) about x=0 under the influence of a force shown in the figure. The period of the SHM is

A body of mass 0.01 kg executes simple harmonic motion (S.H.M.) about x = 0 under the influence of a force shown below: The period of the S.H.M. is

A block of mass 5 kg executes simple harmonic motion under the restoring force of a spring. The amplitude and the time period of the motion are 0.1 m and 3.14 s respectively. Fnd the maximum force exerted by the spring on the block.

A block of mass 5 kg executes simple harmonic motion under the restoring force of a spring. The amplitude and the time period of the motion are 0.1 m and 3.14 s respectively. Find the maximum force exerted by the spring on the block.

A block of mass 5 kg executes simple harmonic motion under the restoring force of a spring. The amplitude and the time period of the motion are 0.1 m and 3.14 s respectively. Find the maximum force exerted by the spring on the block.

A block of mass 2kg executes simple harmonic motion under the reading from at a spring .The angular and the time period of motion are 0.2 cm and 2pi sec respectively Find the maximum force execute by the spring in the block.

A body is executing simple harmonic motion under the action of a force F_(1) with time period 1 s. The time period is 2s when body is acted by another force F_(3) . What will be the total time period when both the forces are acting in same direction simultaneously ?

A particle of mass 0.50 kg executes a simple harmonic motion under a forve F = -(50 n//m)x . If crosses the centre of oscillation with a speed of 10 m//s , find the amplitude of the motion.