" 19."aft7:x:17.5:22.5" it,all "x=?

If 7:x=175:22.5, then find the value of x

17, 9.5, 10.5, 22, 89, ?

The median of the given data. 6, 8, 9, 15, x, x +1 , 21, 22, 25, 29 is 17.5. Find the value of x.

{:(" Class mark ", 12.5, 17.5, 22.5, 27.5, 32.5, 37.5, 42.5),(" Frequency " ,12, 17, 22, 27, 30, 21, 16):} From the distribution, given above construct a frequency table

hoblem -3 x 68.5 40 30 x 10 -40 685 30 40 22.83 62.83 Average marks is 62.83 lem the average marks from the following distribution iculate 10-15 15-20 20-25 30 30-35 rks 5-10 No. of students tion, Marks (CH) No. student (f) Midvalue(x) d Fd 2.5 5-10 10-15 125 15-20 20-25 225 +1 25-30 27.5 2 +15 30-35 +3 32.5 25 Using step deviation formula Assumed Mean (A) 17.5 Common factor (i is 5 30 x 5 17.5 17.5 17.5 t 1.2 18.7 llinnon four An were 5's, 30 were 6's and the 540

If 289=17^(x/5) , then x = ?

Following is a data sample in descending order. If the mean is 18.2 and the mode of this data is 17.5. find the missing numbers. 22.1, 20.9, x , 18.6, y, 17.5 ,13.5

If 5x+y=19 and x-3y=7 , then x+y=

5x-3=x+17