A right circular cone is divided by a plane parallel to its base in two equal volumes. In what ratio will the plane divide the axis of the cone?

The height of a right circular cone is trisected by two planes drawn parallel to its base. Show that the volumes of the three portions starting from the top are in the ratio 1:7:19.

A right circular cone is cut by two planes parallel to the base and trisecting the height. Compare the volumes of three parts into which the cone is divided.

A right circular cone is divided into two portions by a plane parallel to the base and passing through a point which is (1)/(3)rd of the height from the top.The ratio of the volume of the smaller cone to that of the remaining frustum of the cone is (a) 1: 3(b) 1: 9 (c) 1:26 (d) 1:27

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base . The ratio of the volume of the smaller cone to the whole cone is

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base. The ratio of the volume of the smaller cone to the whole cone is:

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base. The ratio of the volume of the smaller cone to the whole cone is: 1:2 (b) 1:4 (c) 1:6 (d) 1:8

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base. The ratio of the volume of the smaller cone to the whole cone is: 1:2 (b) 1:4 (c) 1:6 (d) 1:8

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base.The ratio of the volume of the smaller cone to the whole cone is: 1:2 (b) 1:4 (c) 1:6 (d) 1:8