Find out flux through the given Gaussian surface.

Find out flux through given gaussian surface.

Due to the presence of a point charge at the centre of a spherical Gaussian surface of diatmer alpha , 10^6 Nm^2//C amount of electric flux passes through it. Keeping the point charge at the centre, the Gaussain surface is changed to a cubical Gaussian surface of side a. The flux through the new Gaussian surface will be

Find out the flux through the curved surface of a hemisphere of radius R if it is placed in a uniform electric field E as shown in figure

Find out the flux through the curved surface of a hemisphere of radius R if it is placed in a uniform electric field E as shown in figure

Consider an infinitely long straight uniformly charged wire with linear charge density lambda . Find the total electric flux through the Gaussian surface for the above mentioned charged wire .

If the radius of the Gaussian surface enclosing a charge is halved, how does the electric flux through the Gaussian surface change?

An infinite, uniformly charged sheet with surface charge density sigma cuts through a spherical Gaussian surface of radius R at a distance X from its center, as shown in the figure. The electric flux Phi through the Gaussian surface is .