In two digit numbers, how many times does the digit 5 occur in (i)the ten's place (ii)the units place?

In a two-digit number, the digit at the units place is double the digit in the tens place. The number exceeds the sum of its digits by 18. Find the number.

The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is

The ratio between a two digit number and the sum of the digits of that number is 4:1. If the digit in the unit's place is 3 more than the digit in the ten's place,what is the number?

The ratio between a to digit number and the sum of the digits of that number is 4:1. If the digit in the unit’s place is 3 more than the digit in the ten’s place, then the number is a. 24 b. 63 c. 36 d. 96

The sum of digits of a two digit number is 11. If the digit of ten's place is increased by 5 and the digit at unit's place is decreased by 5 the digit of the number are found to be reversed. Find the origional number.

In a two - digit numbers, the digit at units place is 4 more than the digit at tens place. Find the two digit number. I. Sum of their digits is 10 II. The difference between the number and the number obtained by interchanging the position of the digits is 36.

In a two-digit number the digit in the unit's place is three times the digit in the tenth's place. The sum of the digits is equal to 8. Then, what is the number?