The line `2x -y +6= 0` meets the circle `x^2+y^2 -2y-9 =0` at A and B. Find the equation of the circle on AB as diameter.

Answer the following: The line 2x-y+6=0 meets the circle x^2+y^2+10x+9=0 at A and B.find the equation of circle on Ab as diameter.

If x - y + 1 = 0 meets the circle x^(2) + y^(2) + y - 1 = 0 at A and B , then the equation of the circle with AB as diameter is

If x-y+1=0 meets the circle. x^(2)+y^(2)+y-1=0 at A and B , then the equation of the circle with A B as diameter is

The straight line x+y - 1= 0 cuts the circle x^(2) + y^(2) - 6x - 8y = 0 at A and B. Find the equation of the circle of which AB is a diameter.

The circle x^2+y^2=4 cuts the circle x^2+y^2+2x+3y-5=0 in A and B , Then the equation of the circle on AB as diameter is

If x-y+1=0 meets thwe cicle x^(2)+y^(2)+y-1=0 at a and b, then the equation of the circle with ab as diameter, is

The straight line x+y-1=0 meets the circle .x^(2)+y^(2)-6x-8y=0 at A and B . Then,the equation of : the circle of which AB is a diameter,is

The circle x^(2) + y^(2) + 2x - 4y - 11 = 0 and the line x-y+1=0 intersect at A and B. Find the equation to the circle on AB as diameter.