The shortest distance between the straight lines through the points `A_1 = (6,2,2)` and `A_2=(-4,0,-1),` in the directions of `(1, -2,2)` and `(3,-2,-2)` is

The shortest distance between the straighat lines through the point A_1=(6,2,2) and A_2=(-4,0,-1) in the directions 1,-2,2 and 3,-2,-2 is (A) 6 (B) 8 (C) 12 (D) 9

The shortest distance between the straighat lines through the point A_1=(6,2,2) and A_2=(-4,0,-1) in the directions 1,-2,2 and 3,-2,-2 is (A) 6 (B) 8 (C) 12 (D) 9

The shortest distance between the straight line passing through the point A = (6, 2, 2) and parallel to the vector (1, -2, 2) and the straight line passing through A^(1) = ( -4, 0, -1) and parallel to the vector (3, -2, -2) is

The shortest distance between the line passing through the point (2,-1,1) and parallel to the vector (-1,1,2) and the line passing through (0,3,1) and parallel to vector (2,4,-1) is

Find the shortest distance between the line passing through the point (2,-1, 1) and parallel to the vector (-1, 1, 2) and the straight line passing through (0, 3, 1) and parallel to the vector (2, 4, -1).

Write the formula for the shortest distance between the lines -> r= -> a_1+lambda -> b\ a n d\ -> r= -> a_2+mu -> bdot\

Write the formula for the shortest distance between the lines vec r= vec a_1+lambda vec b_1 a n d\ vec r= vec a_2+mu vec b_2dot\

If the equation of the locus of a point equidistant from the points (a_1, b_1) and (a_2, b_2) is (a_1-a_2)x+(b_1-b_2)y+c=0 , then the value of c is a a2-a2 2+b1 2-b2 2 sqrt(a1 2+b1 2-a2 2-b2 2) 1/2(a1 2+a2 2+b1 2+b2 2) 1/2(a2 2+b2 2-a1 2-b1 2)

If the equation of the locus of a point equidistant from the points (a_1, b_1) and (a_2, b_2) is (a_1-a_2)x+(b_1-b_2)y+c=0 , then the value of c is a a2-a2 2+b1 2-b2 2 sqrt(a1 2+b1 2-a2 2-b2 2) 1/2(a1 2+a2 2+b1 2+b2 2) 1/2(a2 2+b2 2-a1 2-b1 2)