Find the equation of the circle passing through the points `(2, 3)`and `(-1, 1)`and whose centre is on the line `x - 3y - 11 = 0`.

Explanation

To find the equation of the circle passing through the points (2, 3) and (-1, 1) with its center on the line \(x - 3y - 11 = 0\), we can follow these steps:

### Step 1: General Equation of Circle
The general equation of a circle with center \((h, k)\) and radius \(r\) is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]

...