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The axis of a parabola is along the line `y=x` and the distance of its vertex and focus from the origin are `sqrt(2)` and `2sqrt(2)` , respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is `(x+y)^2=(x-y-2)` `(x-y)^2=(x+y-2)` `(x-y)^2=4(x+y-2)` `(x-y)^2=8(x+y-2)`

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The axis of a parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt(2) and 2sqrt(2) , respectively. If vertex and focus both lie in the first quadrant, then find equation of the parabola.

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2) , respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is (a) (x+y)^2=(x-y-2) (b) (x-y)^2=(x+y-2) (c) (x-y)^2=4(x+y-2) (d) (x-y)^2=8(x+y-2)

The axis of parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt(2) and 2sqrt(2) respectively.If vertex and focus both lie in the first quadrant,then the equation of the parabola is:

The axis of parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt2 and 2 sqrt2 respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is :

The axis of parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt2 and 2 sqrt2 respectively. If vertex and focus both lie in the first quadrant, then find the equation of the parabola

The axis of parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt2 and 2 sqrt2 respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is :

The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2), respectively.If vertex and focus both lie in the first quadrant, then the equation of the parabola is (x+y)^(2)=(x-y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=4(x+y-2)(x-y)^(2)=8(x+y-2)

The axis of a parabola is along the line y=x and the distance of its vertex from origin is sqrt(2) and that from its focus is 2sqrt(2) if vertex and focus both lie in the first quadrant then the equatio of the parbola is

The axis of a parabola is along the line y = x and the distance of its vertex from origin is sqrt2 and that from its focus is 2sqrt2 . If vertex and focus both lie in the first quadrant, then the equation of the parabola is

The axis of a parabola is along the line y = x and its vertex and focus are in the first quadrant at distances sqrt2,2sqrt2 respectively, from the origin. The equation of the parabola, is