Find the equation of the circle passing through the points (4, 1) and (6, 5) and whose centre is on the line `4x + y = 16`.

Explanation

To find the equation of the circle that passes through the points (4, 1) and (6, 5), and whose center lies on the line \(4x + y = 16\), we can follow these steps:

### Step 1: Set up the equation of the circle
The general equation of a circle with center \((h, k)\) and radius \(r\) is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]

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