The length of a weigtless spring increaes by 2cm when a weight of 1.0kg in the period of oscillation of the spring and its kinetic energy of oscillation. Take `g=10ms^(-2)`.

The vertical extension in a light spring by a weight of 1 kg, in equilibrium is 9.8 cm. The period of oscillation of the spring, in seconds, will be…………….

A spring is stretched by 5cm by a force 10N. The time period of the oscillations when a mass of 2Kg is suspended by it is

The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm . The period of oscillation

The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm . The period of oscillation

A spring compressed by 0.2 m develops a restoring force of 25 N. A body of mass 5 kg is placed over it. Deduce (i) force constant of the spring (ii) the depression of the spring under the weight of the body and (iii) the period of oscillation, if the body is disturbed. Take g=10 N kg^(-1) .

A mass is suspended from the end of a spring. When the system is oscillating the amplitude of oscillation is 4 cm and maximum kinetic energy of oscillation of the system is 1J. Then the force constant of the spring is

A spring is stretched by 0.20 m , when a mass of 0.50 kg is suspended. When a mass of 0.25 kg is suspended, then its period of oscillation will be (g = 10 m//s^(2))

A pan with a set of weights is attached to a light spring. The period of vertical oscillations is 0.5s . When some additional weights are put in pan, the period of oscillations increases by 0.1s . The extension caused by the additional weights is