`int_0^pi sqrt(2)(1+cosx)^(7/2)dx=` (A) `32/35` (B) `64/35` (C) `256/35` (D) `512/35`

int_(256)^( pi)sqrt(2)(1+cos x)^((7)/(2))dx=(A)(32)/(35)(B)(64)/(35)(C)(256)/(35)(D)(512)/(35)

4/7 xx ? =32/35

2^(3^2) = (a)64 (b) 32 (c)256 (d) 512

Find: 2^(3^2) = (a)64 (b) 32 (c)256 (d) 512

int_0^3 x(3-x)^(3/2) dx= (A) (108sqrt(3))/35 (B) -(108sqrt(3))/35 (C) (54sqrt(3))/35 (D) none of these

int_0^3 x(3-x)^(3/2) dx= (A) (108sqrt(3))/35 (B) -(108sqrt(3))/35 (C) (54sqrt(3))/35 (D) none of these

7 : 32 : : 35 : ?

(35)/(7)+(93)/(2)

A line is perpendicular to the line 2x-3y+5=0 and passes through the points (15, beta) and (7, 17) then value of beta will be equal to (A) 35/3 (B) -35/3 (C) 5 (D) -5

Factorise: 1/35 + 12/35a + a^(2)