The product of the perpendiculars from `(-1,2)` to the pair of lines `2x^2 – 5 xy + 2y^2 = 0`

The product of the perpendiculars from (-1, 2) to the pair of lines 2x^(2)-5xy+2y^(2)=0

The product of the perpendiculars from (-1,2) to the pair of lines 2x^(2)5xy+2y^(2)=0

The product of the perpendiculars from (-1,2) to the pair of-lines 2 x^(2)-5 x y+2 y^(2)=0 is

The product of the perpendiculars from (1, 1) to the pair of lines x^(2)+4 x y+3 y^(2)=0 is

The product of the perpendiculars drawn from (2,-1) to the pair of lines x^(2)-3xy+2y^(2)=0 is

The product of the perpendicular distances from (1, -1) to the pair of lines x^(2)-4xy+y^(2)=0 , is

If the product of the perpendicular distances from (1, k) to the pair of lines x^(2)-4xy+y^(2)=0 is (3)/(2) units, then k=

The product of the perpendiculars drawn from the point (1,2) to the pair of lines x^(2)+4xy+y^(2)=0 is

The product of the perpendiculars drawn from the point (1,2) to the pair of lines x^(2)+4xy+y^(2)=0 is